Trắc nghiệm Đạo hàm cấp hai có đáp án có đáp án

 \(y\text{'}\text{'}\text{'}=12\left({x}^{2}+1\right)\)

 \(y\text{'}\text{'}\text{'}=24\left({x}^{2}+1\right)\)

 \(y\text{'}\text{'}\text{'}=24\left(5{x}^{2}+3x\right)\)

 \(y\text{'}\text{'}\text{'}=-12\left({x}^{2}+1\right)\)

 \(y\text{'}\text{'}=\frac{1}{\left(2x+5\right)\sqrt{2x+5}}\)

 \(y\text{'}\text{'}=\frac{1}{\sqrt{2x+5}}\)

 \(y\text{'}\text{'}=-\frac{1}{\left(2x+5\right)\sqrt{2x+5}}\)

 \(y\text{'}\text{'}=-\frac{1}{\sqrt{2x+5}}\)

 \(y\text{'}\text{'}=-\frac{2{x}^{3}+3x}{(1+{x}^{2})\sqrt{1+{x}^{2}}}\)

 \(y\text{'}\text{'}=-\frac{2{x}^{1}+1}{\sqrt{1+{x}^{2}}}\)

 \(y\text{'}\text{'}=\frac{2{x}^{3}+3x}{(1+{x}^{2})\sqrt{1+{x}^{2}}}\)

 \(y\text{'}\text{'}=\frac{2{x}^{1}+1}{\sqrt{1+{x}^{2}}}\)

 \(y\text{'}\text{'}\text{'}=80{\left(2x+5\right)}^{3}\)

 \(y\text{'}\text{'}\text{'}=480{\left(2x+5\right)}^{2}\)

 \(y\text{'}\text{'}\text{'}=-480{\left(2x+5\right)}^{2}\)

 \(y\text{'}\text{'}\text{'}=-80{\left(2x+5\right)}^{3}\)

 \(y\text{'}\text{'}=-\frac{2\mathrm{sin}x}{{\mathrm{cos}}^{3}x}\)

 \(y\text{'}\text{'}=\frac{1}{{\mathrm{cos}}^{3}x}\)

 \(y\text{'}\text{'}=-\frac{1}{{\mathrm{cos}}^{2}x}\)

 \(y\text{'}\text{'}=\frac{2\mathrm{sin}x}{{\mathrm{cos}}^{3}x}\)