Bài tập Hai phân thức bằng nhau (có lời giải)

\(\frac{{y}^{3}+10y}{3{y}^{2}+y}\);

\(\frac{{y}^{3}+10y}{‐\left(3{y}^{2}+y\right)}\);

\(\frac{‐\left({y}^{3}+10y\right)}{‐\left(3{y}^{2}+y\right)}\);

\(‐\frac{‐\left({y}^{3}+10y\right)}{‐\left(3{y}^{2}+y\right)}\).

\(\frac{x+3}{x+1}\)và \(\frac{\left(x+3\right)\left(x+1\right)}{{x}^{2}-1}\);

\(\frac{7{y}^{2}}{5}\)và \(\frac{3x{y}^{2}}{2x}\)

\(\frac{2x\left(x-5\right)}{3\left(5-x\right)}\)và \(\frac{5x}{2}\);

 \(\frac{{x}^{2}-2}{5\left(x+2\right)}\)và \(\frac{x-2}{5}\).

\(‐\frac{‐{z}^{4}+z+2}{{z}^{2}+1}\);

\(‐\frac{‐{z}^{4}-z+2}{{z}^{2}+1}\);

\(\frac{‐{z}^{4}+z-2}{‐{z}^{2}+1}\);

\(\frac{‐{z}^{4}+z-2}{‐{z}^{2}+1}\).

\(\frac{5x+5}{5x}\)= \(\frac{x+1}{x}\);

\(\frac{{x}^{2}-9}{x-3}\)= x + 3;

\(\frac{{x}^{2}-9}{x-3}\)= x – 3;

\(\frac{5x+5}{5x}\)= 5.

\(\frac{20xy}{28y}\)và \(\frac{5y}{7}\);

\(\frac{‐1}{2}\)và \(\frac{15x}{‐30x}\);

\(\frac{7}{5y}\)và \(\frac{5y}{2xy}\);

\(\frac{‐1}{15x}\)và \(\frac{‐2}{‐30x}\).