Đề thi cuối kì 2 Toán 11 cấu trúc mới có đáp án - Đề 5

 \({\mathrm{y}}^{\text{'}\text{'}}=-\mathrm{cosx}\)

 \({\mathrm{y}}^{\text{'}\text{'}}=\mathrm{cosx}\)

 \({\mathrm{y}}^{\text{'}\text{'}}=-\mathrm{sinx}\)

 \({\mathrm{y}}^{\text{'}\text{'}}=\mathrm{sinx}\)

 \(\mathrm{y}={3}^{\mathrm{x}}\)

 \(\mathrm{y}={\left(\frac{1}{3}\right)}^{\mathrm{x}}\)

 \(\mathrm{y}={\mathrm{log}}_{3}\mathrm{x}\)

 \(\mathrm{y}={\mathrm{log}}_{\frac{1}{3}}\mathrm{x}\)

 \(30°\)

 \(45°\)

 \(90°\)

 \(60°\)

 \(\mathrm{x}=3\)

 \(\mathrm{x}=25\)

 \(\mathrm{x}=29\)

 \(\mathrm{x}=18\)

 \({\mathrm{A}}^{\text{'}}\notin \left(\mathrm{P}\right)\)

 \({\mathrm{AA}}^{\text{'}}\perp \left(\mathrm{P}\right)\)

 \({\mathrm{AA}}^{\text{'}}//\left(\mathrm{P}\right)\)

 \({\mathrm{AA}}^{\text{'}}\subset \left(\mathrm{P}\right)\)

 \({\mathrm{a}}^{\mathrm{x}}.{\mathrm{a}}^{\mathrm{y}}={\mathrm{a}}^{\mathrm{x}+\mathrm{y}}\)

 \({\mathrm{a}}^{\mathrm{x}}+{\mathrm{a}}^{\mathrm{y}}={\mathrm{a}}^{\mathrm{x}.\mathrm{y}}\)

 \({\mathrm{a}}^{\mathrm{x}}+{\mathrm{a}}^{\mathrm{y}}={\mathrm{a}}^{\mathrm{x}+\mathrm{y}}\)

 \({\mathrm{a}}^{\mathrm{x}}.{\mathrm{a}}^{\mathrm{y}}={\mathrm{a}}^{\mathrm{x}.\mathrm{y}}\)